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-.0004x^2+60x-220.000=0
We add all the numbers together, and all the variables
-0.0004x^2+60x-220=0
a = -0.0004; b = 60; c = -220;
Δ = b2-4ac
Δ = 602-4·(-0.0004)·(-220)
Δ = 3599.648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-\sqrt{3599.648}}{2*-0.0004}=\frac{-60-\sqrt{3599.648}}{-0.0008} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+\sqrt{3599.648}}{2*-0.0004}=\frac{-60+\sqrt{3599.648}}{-0.0008} $
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